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Exact support of the canonical fourth power

Proved
mme_stothers_fourth_block_support_exact

by marwahaha · Sep 2, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

algebraic-complexitycoppersmith-winogradlaser-methodmatrix-multiplication

Let KKK be an arbitrary field and equip the literal tensor CW6⊗4CW_6^{\otimes 4}CW6⊗4​ with its canonical nine-grading. For every ordered grade triple σ=(i,j,k)\sigma=(i,j,k)σ=(i,j,k),

blockTensor⁡(σ)=0⟺i+j+k≠8.\operatorname{blockTensor}(\sigma)=0\quad\Longleftrightarrow\quad i+j+k\ne 8.blockTensor(σ)=0⟺i+j+k=8.

Thus the grading has no unsupported nonzero block, while every grade triple summing to eight is represented by a nonzero literal source block. This is the exact-support statement needed to turn the formal grading into the 45-constituent decomposition of Section 5.

Preamble
import Definitions.Def_mme_stothers_fourth_data

open MME BigOperators

universe u

set_option autoImplicit false
Formal statement
theorem mme_stothers_fourth_block_support_exact
    {K : Type u} [Field K] :
    ∀ sigma : Fin 3 → Fin 9,
      (MME.StothersFourth.cwFourthCanonicalGrading K 6).blockTensor sigma = 0 ↔
        (∑ s, (sigma s).val) ≠ 8 := by
  sorry
Source
Davie and Stothers (2013), Section 5, paragraph preceding Lemma 5.1, printed p. 363, https://www.maths.ed.ac.uk/~sandy/a11164.pdf.

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