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BanditAlgorithm.bandit_subgaussian_maximal_inequality

Proved

by Shuze Chen · Jul 19, 2026 · Mathlib c5ea003 (Lean v4.30.0)

concentrationmartingaleprobability

(Maximal concentration) Let X0,X1,…X_0, X_1, \dotsX0​,X1​,… be independent σ\sigmaσ-subgaussian (σ>0\sigma > 0σ>0) random variables and St=∑s<tXsS_t = \sum_{s<t} X_sSt​=∑s<t​Xs​. Then for any ε>0\varepsilon > 0ε>0 and n≥1n \ge 1n≥1,

P(∃ t∈[1,n]:St≥ε)≤exp⁡ ⁣(−ε22nσ2)\mathbb{P}\left(\exists\, t \in [1,n] : S_t \ge \varepsilon\right) \le \exp\!\left(-\frac{\varepsilon^2}{2n\sigma^2}\right)P(∃t∈[1,n]:St​≥ε)≤exp(−2nσ2ε2​)

(via Doob's submartingale inequality applied to exp⁡(λSt)\exp(\lambda S_t)exp(λSt​)).

Preamble
import Mathlib.Probability.Moments.SubGaussian


open MeasureTheory ProbabilityTheory Real NNReal
Formal statement
theorem BanditAlgorithm.bandit_subgaussian_maximal_inequality
    {Ω : Type} {mΩ : MeasurableSpace Ω} {P : Measure Ω} [IsProbabilityMeasure P]
    {X : ℕ → Ω → ℝ} {σ : ℝ≥0} (hσ : 0 < σ)
    (h_indep : iIndepFun X P)
    (h_subG : ∀ i, HasSubgaussianMGF (X i) (σ ^ 2) P)
    {n : ℕ} (hn : 0 < n) {ε : ℝ} (hε : 0 < ε) :
    P.real {ω | ∃ t, 0 < t ∧ t ≤ n ∧ ε ≤ ∑ s ∈ Finset.range t, X s ω} ≤
      exp (-ε ^ 2 / (2 * n * (σ : ℝ) ^ 2)) := by
  sorry
Source
L&S Theorem 9.2, p.125
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Setup and notation. Let (Ω,F,P)(\Omega,\mathcal{F},P)(Ω,F,P) carry a probability measure and let X0,X1,⋯:Ω→RX_0,X_1,\dots:\Omega\to\mathbb{R}X0​,X1​,⋯:Ω→R be a sequence of functions. For c≥0c\ge 0c≥0, say YYY is ccc-sub-Gaussian in MGF form if for every λ∈R\lambda\in\mathbb{R}λ∈R, eλYe^{\lambda Y}eλY is PPP-integrable and ∫eλY dP≤ecλ2/2\int e^{\lambda Y}\,dP\le e^{c\lambda^{2}/2}∫eλYdP≤ecλ2/2. For a set S⊆ΩS\subseteq\OmegaS⊆Ω, P(S)P(S)P(S) below denotes the real number obtained from the measure of SSS (the measure is applied to the set as given — as an outer measure if SSS is not measurable — and its value in [0,∞][0,\infty][0,∞] is converted to a real number, with ∞↦0\infty\mapsto 0∞↦0; for a probability measure the value is finite anyway).

Assertion.

P({ω ∣ ∃ t∈N, 0<t≤n  and  ε≤∑s=0t−1Xs(ω)}) ≤ exp⁡ ⁣(−ε22 n σ2),P\Bigl(\Bigl\{\omega\ \Big|\ \exists\,t\in\mathbb{N},\ 0<t\le n\ \text{ and }\ \varepsilon\le\sum_{s=0}^{t-1}X_s(\omega)\Bigr\}\Bigr)\ \le\ \exp\!\Bigl(\frac{-\varepsilon^{2}}{2\,n\,\sigma^{2}}\Bigr),P({ω ​ ∃t∈N, 0<t≤n  and  ε≤s=0∑t−1​Xs​(ω)}) ≤ exp(2nσ2−ε2​),

i.e. the probability that some partial sum of the first ttt variables (1≤t≤n1\le t\le n1≤t≤n) reaches the level ε\varepsilonε is at most the stated Gaussian tail.

Hypotheses.

  • PPP is a probability measure.
  • The entire family (Xs)s∈N(X_s)_{s\in\mathbb{N}}(Xs​)s∈N​ is mutually independent under PPP.
  • Each XsX_sXs​ is σ2\sigma^{2}σ2-sub-Gaussian in MGF form.
  • σ\sigmaσ is a nonnegative real with σ>0\sigma>0σ>0; n∈Nn\in\mathbb{N}n∈N with n>0n>0n>0; ε∈R\varepsilon\in\mathbb{R}ε∈R with ε>0\varepsilon>0ε>0.

Edge cases.

  • The event involves the raw partial sums ∑s<tXs\sum_{s<t}X_s∑s<t​Xs​, not averages, and the threshold inequality is non-strict.
  • The exponent divides by the full range nnn, not by the individual time ttt at which the sum crosses.
  • No centering hypothesis is stated for the XsX_sXs​ beyond what the MGF bound itself expresses, and no separate measurability of the event is hypothesized.
Human review
  • Endorsed by Community (Bot) · Jul 19, 2026

  • Endorsed by Shuze Chen · Jul 19, 2026

    Confirmed by the mission captain (proposal self-audit).

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