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Proof of Theorem 1: the core of vvv is {(3,0,0,6,3)}\{(3,0,0,6,3)\}{(3,0,0,6,3)}

Proved
MonotonicSolutions.CoreRules.core_youngV

by mikedeng1 · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

cooperative-gamescorecounterexamplep2o-batch-p100bp2o-gran-per-chapterp2o-plan-paperp2o-v1

Let vvv be the five-player game of the proof of Theorem 1: identical to the game www (defined from S1={3,5}S_1 = \{3,5\}S1​={3,5}, S2={1,2,3}S_2 = \{1,2,3\}S2​={1,2,3}, S3={1,3,4}S_3 = \{1,3,4\}S3​={1,3,4}, S4={2,4,5}S_4 = \{2,4,5\}S4​={2,4,5}, S5={1,2,4,5}S_5 = \{1,2,4,5\}S5​={1,2,4,5} with w(S1)=w(S2)=3w(S_1)=w(S_2)=3w(S1​)=w(S2​)=3, w(S3)=w(S4)=w(S5)=9w(S_3)=w(S_4)=w(S_5)=9w(S3​)=w(S4​)=w(S5​)=9, w(N)=11w(N)=11w(N)=11, and w(S)=max⁡Sk⊆Sw(Sk)w(S) = \max_{S_k\subseteq S} w(S_k)w(S)=maxSk​⊆S​w(Sk​) or 000 otherwise), except that v(S5)=v(N)=12v(S_5) = v(N) = 12v(S5​)=v(N)=12.

Then the core of vvv consists of exactly one point:

C(v)={xˉˉ},xˉˉ=(3,0,0,6,3).C(v) = \{\bar{\bar x}\}, \qquad \bar{\bar x} = (3, 0, 0, 6, 3).C(v)={xˉˉ},xˉˉ=(3,0,0,6,3).

Compared with the core point (0,1,2,7,1)(0,1,2,7,1)(0,1,2,7,1) of www, players 2 and 4 receive less, although every coalition containing them has weakly increased in value.

Formalization Note The core is the published Supermodularity.Cooperative.Core Finset.univ; xˉˉ\bar{\bar x}xˉˉ is ![3, 0, 0, 6, 3] (paper's player kkk = Lean index k−1k-1k−1).

Preamble
import Mathlib
import Definitions.Def_Supermodularity_Cooperative_Core
import Definitions.Def_MonotonicSolutions_CoreRules_Game
import Definitions.Def_MonotonicSolutions_CoreRules_YoungGames
Formal statement
namespace MonotonicSolutions.CoreRules

theorem core_youngV :
    Supermodularity.Cooperative.Core Finset.univ youngV.1 = {![3, 0, 0, 6, 3]} := by sorry

end MonotonicSolutions.CoreRules
Source
Young, Monotonic Solutions of Cooperative Games, Int. J. Game Theory 14 (1985), p. 69, proof of Theorem 1 (the unique core element of v is (3, 0, 0, 6, 3))
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What the Lean code literally says, in plain math · claude-opus-5-5

The game vvv has players 0,…,40, \dots, 40,…,4 and is defined from C0={2,4}C_0 = \{2,4\}C0​={2,4}, C1={0,1,2}C_1 = \{0,1,2\}C1​={0,1,2}, C2={0,2,3}C_2 = \{0,2,3\}C2​={0,2,3}, C3={1,3,4}C_3 = \{1,3,4\}C3​={1,3,4}, C4={0,1,3,4}C_4 = \{0,1,3,4\}C4​={0,1,3,4} as follows:

  • v(N)=12v(N) = 12v(N)=12;
  • for any other SSS, v(S)v(S)v(S) is the maximum of valk\mathrm{val}_kvalk​ over the Ck⊆SC_k \subseteq SCk​⊆S, where (val0,…,val4)=(3,3,9,9,12)(\mathrm{val}_0, \dots, \mathrm{val}_4) = (3,3,9,9,12)(val0​,…,val4​)=(3,3,9,9,12);
  • v(S)=0v(S) = 0v(S)=0 if SSS contains no CkC_kCk​.

The statement asserts that the core of vvv is exactly one point:

Core⁡(N,v)={(3, 0, 0, 6, 3)}.\operatorname{Core}(N, v) = \{(3,\,0,\,0,\,6,\,3)\}.Core(N,v)={(3,0,0,6,3)}.

The coordinates are listed for players 0,1,2,3,40, 1, 2, 3, 40,1,2,3,4. The core is an imported definition whose code was not provided. Its description elsewhere in the chapter is the set of efficient vectors xxx with v(S)≤∑i∈Sxiv(S) \le \sum_{i \in S} x_iv(S)≤∑i∈S​xi​ for every coalition SSS.

Degenerate cases. The statement is about one concrete game. There are no parameters, so no degenerate cases arise.

Human review
  • Endorsed by Shuze Chen · Sep 28, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Sep 28, 2026

    Confirmed by the mission captain (proposal self-audit).

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