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Sums of self-concordant functions

Proved
ConvexOptimization.self_concordant_add

by Shuze Chen · Aug 13, 2026 · Mathlib c5ea003 (Lean v4.30.0)

convex-optimizationinterior-pointself-concordance

Self-concordance is preserved by addition.

Let Ω⊆Rn\Omega \subseteq \mathbb{R}^nΩ⊆Rn be open and let fff and hhh both be self-concordant on Ω\OmegaΩ — convex, C3C^3C3, and satisfying ∣φ′′′(0)∣≤2φ′′(0)3/2|\varphi'''(0)| \le 2\varphi''(0)^{3/2}∣φ′′′(0)∣≤2φ′′(0)3/2 for every line restriction φ(t)=f(x+tv)\varphi(t) = f(x + tv)φ(t)=f(x+tv) with x∈Ωx \in \Omegax∈Ω. Then f+hf + hf+h is self-concordant on Ω\OmegaΩ:

f,h self-concordant on Ω  ⟹  f+h self-concordant on Ω.f, h \text{ self-concordant on } \Omega \;\Longrightarrow\; f + h \text{ self-concordant on } \Omega .f,h self-concordant on Ω⟹f+h self-concordant on Ω.

The proof is the elementary inequality ∣u+v∣≤2(a3/2+b3/2)≤2(a+b)3/2|u + v| \le 2(a^{3/2} + b^{3/2}) \le 2(a+b)^{3/2}∣u+v∣≤2(a3/2+b3/2)≤2(a+b)3/2 for the pieces, and the practical consequence is a calculus: a barrier assembled from many self-concordant terms is self-concordant, so one never verifies the third-derivative condition for a composite function directly.

Formalization Note Openness of Ω is an explicit hypothesis, and it is genuinely needed: at a boundary point the iterated derivatives of the line restriction are junk values and the inequality would be asserted about meaningless quantities. Source: B&V §9.6.1, p. 497.

Preamble
import Mathlib
import Definitions.Def_ConvexOptimization_selfConcordance

open scoped RealInnerProductSpace ENNReal
open MeasureTheory

Formal statement
theorem ConvexOptimization.self_concordant_add {n : ℕ} (Ω : Set (EuclideanSpace ℝ (Fin n)))
    (hΩo : IsOpen Ω) (f h : EuclideanSpace ℝ (Fin n) → ℝ)
    (hf : IsSelfConcordantOn Ω f) (hh : IsSelfConcordantOn Ω h) :
    IsSelfConcordantOn Ω (f + h) := by
  sorry
Source
Boyd & Vandenberghe 2004, Convex Optimization, Cambridge University Press (seventh printing with corrections, 2009), https://web.stanford.edu/~boyd/cvxbook/, pp. 499, §9.6.1 (self-concordance is preserved by addition). Openness of the domain is an explicit hypothesis: the line-restriction derivatives carry junk values at boundary points
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What the Lean code literally says, in plain math · claude-fable-5

For every natural number nnn, every open set Ω⊆Rn\Omega \subseteq \mathbb{R}^nΩ⊆Rn (openness is an explicit hypothesis), and all total functions f,h:Rn→Rf, h : \mathbb{R}^n \to \mathbb{R}f,h:Rn→R such that both fff and hhh are self-concordant on Ω\OmegaΩ, the pointwise sum f+hf + hf+h is self-concordant on Ω\OmegaΩ. Here "FFF is self-concordant on Ω\OmegaΩ" abbreviates the conjunction: (i) Ω\OmegaΩ is convex and F(ax+by)≤aF(x)+bF(y)F(ax+by) \le aF(x) + bF(y)F(ax+by)≤aF(x)+bF(y) for all x,y∈Ωx, y \in \Omegax,y∈Ω and a,b≥0a, b \ge 0a,b≥0 with a+b=1a + b = 1a+b=1; (ii) FFF is three times continuously differentiable on Ω\OmegaΩ (within-set sense); (iii) for every x∈Ωx \in \Omegax∈Ω and every vector v∈Rnv \in \mathbb{R}^nv∈Rn (arbitrary, possibly zero, possibly leaving Ω\OmegaΩ), the line restriction φ(t)=F(x+tv)\varphi(t) = F(x + tv)φ(t)=F(x+tv) satisfies ∣φ′′′(0)∣≤2(φ′′(0))3/2|\varphi'''(0)| \le 2(\varphi''(0))^{3/2}∣φ′′′(0)∣≤2(φ′′(0))3/2, with derivatives at 000 taken as total operators (junk values if φ\varphiφ is insufficiently differentiable at 000) and with the real power satisfying b3/2=0b^{3/2} = 0b3/2=0 whenever b≤0b \le 0b≤0. The same constant 222 and exponent 3/23/23/2 appear in both hypotheses and conclusion — there is no rescaling of the sum. Edge cases: Ω=∅\Omega = \emptysetΩ=∅ makes both hypotheses and the conclusion vacuously true; no nonemptiness or properness of Ω\OmegaΩ is assumed.

Human review
  • Endorsed by Community (Bot) · Aug 13, 2026

  • Endorsed by Shuze Chen · Aug 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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