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Geometric rank-one dependence makes a determinant affine in its parameter

Proved
EulerMascheroni.Arithmetic.geometric_rank_one_determinant_affine

by shivm · Sep 11, 2026 · Mathlib 0df444a (Lean v4.33.1)

determinantseuler-constantlinear-algebra

Let RRR be a commutative ring, AAA an (n+1)×(n+1)(n+1)\times(n+1)(n+1)×(n+1) matrix over RRR, and r∈Rr\in Rr∈R. There exist a,b∈Ra,b\in Ra,b∈R, independent of ttt, such that

det⁡(Aij+ri+jt)=at+b(t∈R).\det\bigl(A_{ij}+r^{i+j}t\bigr)=at+b\qquad(t\in R).det(Aij​+ri+jt)=at+b(t∈R).

Subtracting rir^iri times the first row from row i>0i>0i>0 removes the parameter from every row except the first; multilinearity then gives the assertion.

This is an obstruction to a naive higher-degree Hankel strategy for the Euler–Gompertz constant. Raw factorial remainders have the form mk(t)=(−1)k(t−Sk)m_k(t)=(-1)^k(t-S_k)mk​(t)=(−1)k(t−Sk​), where Sk=∑j<k(−1)jj!S_k=\sum_{j<k}(-1)^j j!Sk​=∑j<k​(−1)jj!. Their Hankel matrices have precisely the displayed form with r=−1r=-1r=−1, so increasing the determinant size still produces an affine expression in ttt. The theorem does not rule out Hankel determinants of differently normalized or transformed Padé errors.

Preamble
import Mathlib
Formal statement
theorem EulerMascheroni.Arithmetic.geometric_rank_one_determinant_affine {R : Type*} [CommRing R] (n : ℕ)
    (A : Matrix (Fin (n+1)) (Fin (n+1)) R) (r : R) :
    ∃ a b : R, ∀ t : R,
      Matrix.det (fun i j => A i j + r^(i.val+j.val)*t) = a*t+b := by sorry
Source
Elementary determinant row operations. Application prompted by Matala-aho and Zudilin, Euler factorial series and global relations, https://arxiv.org/html/1703.02633, Section 4; no novelty is claimed for the rank-one determinant identity.

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