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A prime-digit reduction for the factorial-weighted P2 denominator

Proved
EulerMascheroni.P2.factorial_binomial_prime_digit

by shivm · Sep 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

binomial-coefficientsformalizationirrationalitynumber-theory

Let ppp be any prime and let a,ba,ba,b be natural numbers with 0≤b<p0\le b<p0≤b<p. Define

Un=∑j=0nj!(nj)3(2n−jn)2.U_n=\sum_{j=0}^{n}j!\binom nj^3\binom{2n-j}{n}^{2}.Un​=j=0∑n​j!(jn​)3(n2n−j​)2.

Then

Uap+b≡(2aa)2Ub(modp).U_{ap+b}\equiv\binom{2a}{a}^{2}U_b\pmod p.Uap+b​≡(a2a​)2Ub​(modp).

The identity holds for arbitrary aaa, including indices larger than p2p^2p2, and includes the prime 222. Together with the exact identity Un=n!QnU_n=n!Q_nUn​=n!Qn​, it reduces the residue of the P2 denominator to its low base-ppp digit and a central binomial factor from the higher digits. It is an unconditional finite congruence; no numerator or global gcd estimate is asserted.

Preamble
import Mathlib.Data.Nat.Choose.Lucas
import Mathlib.Algebra.BigOperators.ModEq
open scoped BigOperators
Formal statement
theorem EulerMascheroni.P2.factorial_binomial_prime_digit (a b p : ℕ) (hp : p.Prime) (hb : b < p) :
    (∑ j ∈ Finset.range (a*p+b+1),
      j.factorial * ((a*p+b).choose j)^3 * ((2*(a*p+b)-j).choose (a*p+b))^2) ≡
    (2*a).choose a ^ 2 *
      (∑ j ∈ Finset.range (b+1), j.factorial * (b.choose j)^3 * ((2*b-j).choose b)^2)
      [MOD p]  := by sorry
Source
Elementary consequence of Lucas’s theorem and factorial truncation, with a complete Lean proof supplied here. The denominator family is the p=2, x=1 specialization of Van Assche–Wolfs, arXiv:2404.09799v3, Section 5, https://arxiv.org/html/2404.09799v3#S5. The digit congruence is a derived auxiliary identity, not a named result in that paper; no bibliographic novelty is claimed.

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