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Parseval's theorem, mean square convergence

Proved
Rudin.ch08_parseval_L2_conv

by Lucas · Sep 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisfourier-analysis

Let f:R→Cf: \mathbb{R} \to \mathbb{C}f:R→C be a 2π2\pi2π-periodic function such that fff and ∣f∣2|f|^2∣f∣2 are Riemann-integrable on [−π,π][-\pi, \pi][−π,π]. Let sN(f;x)s_N(f; x)sN​(f;x) be the NNN-th partial sum of the Fourier series of fff, and let ∥h∥2=(12π∫−ππ∣h(x)∣2dx)1/2\|h\|_2 = \left( \frac{1}{2\pi} \int_{-\pi}^{\pi} |h(x)|^2 dx \right)^{1/2}∥h∥2​=(2π1​∫−ππ​∣h(x)∣2dx)1/2 be the L2L^2L2 norm. Then the Fourier series of fff converges to fff in the mean square sense:

lim⁡N→∞∥f−sN(f)∥2=0.\lim_{N \to \infty} \|f - s_N(f)\|_2 = 0.N→∞lim​∥f−sN​(f)∥2​=0.

This is the completeness statement for the trigonometric system, relying on the fact that continuous periodic functions can be uniformly approximated by trigonometric polynomials (Theorem 8.15).

Preamble
import Mathlib
import Definitions.Def_Rudin_ch08_fourier

open Filter Topology
Formal statement
namespace Rudin

/-- Rudin, Theorem 8.16 (Parseval's theorem, part 1): the Fourier series of a Riemann-integrable
`2π`-periodic function `f` converges to `f` in the mean square sense. -/
theorem ch08_parseval_L2_conv (f : ℝ → ℂ) (hfper : HasPeriodTwoPi f)
    (hf : IntervalIntegrable f MeasureTheory.volume (-Real.pi) Real.pi)
    (hf2 : IntervalIntegrable (fun x => ‖f x‖ ^ 2) MeasureTheory.volume (-Real.pi) Real.pi) :
    Tendsto (fun N => L2Norm (fun x => f x - fourierPartialSum f N x)) atTop (𝓝 0) := by sorry

end Rudin
Source
Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976, Chapter 8, pp. 190-191, Theorem 8.16

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