Multiplicativity of the Herbrand quotient in a short exact sequence
ProvedgroupCohomology.natCard_H2_mul_of_shortExactLet be a group that is finite and cyclic, and let be a short complex in the category of -linear representations of , assumed to be short exact, i.e. to be a short exact sequence of -modules. Assume further that each of the six groups and , for , is finite. Then the cardinalities of these six groups satisfy
where the cardinalities are taken as natural numbers via Nat.card. This is the cross-multiplied form of the multiplicativity of the Herbrand quotient , namely , stated without division so that no invertibility or non-vanishing hypothesis is needed.
This is the classical statement that the Herbrand quotient of a -module, finite cyclic, is multiplicative in short exact sequences, in a purely integral form. It serves as the counting device behind the two results that cite it: the equality for a short exact sequence whose outer cohomology is trivial, and the computation of for a short exact sequence with a term isomorphic to a trivial representation.
import Mathlib set_option maxHeartbeats 4000000 set_option synthInstance.maxHeartbeats 400000 set_option backward.isDefEq.respectTransparency.types false set_option autoImplicit false universe u open CategoryTheory groupCohomology
theorem groupCohomology.natCard_H2_mul_of_shortExact
{G : Type} [Group G] [Finite G] [IsCyclic G]
{X : ShortComplex (Rep ℤ G)} (hX : X.ShortExact)
[Finite (H1 X.X₁)] [Finite (H1 X.X₂)] [Finite (H1 X.X₃)]
[Finite (H2 X.X₁)] [Finite (H2 X.X₂)] [Finite (H2 X.X₃)] :
Nat.card (H2 X.X₂) * Nat.card (H1 X.X₁) * Nat.card (H1 X.X₃)
= Nat.card (H1 X.X₂) * Nat.card (H2 X.X₁) * Nat.card (H2 X.X₃) := by sorry