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The source's Claim: the gcd of the ppp-adic valuations is invariant under a move

Proved
IMO2026P1.gcdExp_invariant

by moutei · Sep 20, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsgcdimoinvariantnumber-theory

The heart of the problem. Fix a prime ppp. The gcd of the ppp-adic valuations of the entries is unchanged by any move.

The source's proof: if νp(m)=x\nu_p(m) = xνp​(m)=x and νp(n)=y\nu_p(n) = yνp​(n)=y with x≤yx \le yx≤y, then the move produces valuations νp(gcd⁡(m,n))=x\nu_p(\gcd(m,n)) = xνp​(gcd(m,n))=x and νp(lcm⁡(m,n)/gcd⁡(m,n))=y−x\nu_p(\operatorname{lcm}(m,n)/\gcd(m,n)) = y - xνp​(lcm(m,n)/gcd(m,n))=y−x; and since gcd⁡(x,y−x)=gcd⁡(x,y)\gcd(x, y-x) = \gcd(x,y)gcd(x,y−x)=gcd(x,y), the gcd over the whole board is unmoved. In the source's words, the board is running "essentially a 2026-number Euclidean algorithm", one per prime, and what a Euclidean algorithm preserves is the gcd.

Both parts of the problem follow from this: at a terminal board the valuations are (νp(M),0,…,0)(\nu_p(M), 0, \ldots, 0)(νp​(M),0,…,0), whose gcd is νp(M)\nu_p(M)νp​(M), so νp(M)\nu_p(M)νp​(M) equals the gcd of the starting valuations for every ppp — a quantity fixed by the starting board alone.

Primality of ppp is carried because the source says "fix a prime ppp". It does no work in the argument: for a non-prime ppp every valuation is 000 and both sides are 000, so the statement would hold without it, but that branch is vacuous and is not the source's claim.

Preamble
import Definitions.Def_IMO2026P1_Blackboard
import Mathlib.Tactic
Formal statement
open IMO2026P1

theorem IMO2026P1.gcdExp_invariant (p : ℕ) (hp : p.Prime) {s t : Board} (h : Move s t) :
    gcdExp p t = gcdExp p s := by sorry
Source
IMO 2026 Problem 1, proposed by Giancarlo Kerg (LUX). Statement and solution: Evan Chen, IMO 2026 Solution Notes, section 1.1, updated 8 September 2026, https://web.evanchen.cc/exams/IMO-2026-notes.pdf
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What the Lean code literally says, in plain math · claude-opus-5

IMO2026P1.gcdExp_invariant

What the statement says. For every natural number ppp, if ppp is prime, then for all finite multisets sss and ttt of natural numbers (both left implicit, to be inferred from the move hypothesis) such that there is a move from sss to ttt, the two natural numbers Gp(t)G_p(t)Gp​(t) and Gp(s)G_p(s)Gp​(s) are equal:

Gp(t)=Gp(s).G_p(t) = G_p(s).Gp​(t)=Gp​(s).

The quantity GpG_pGp​ unfolded. For a board uuu, Gp(u)G_p(u)Gp​(u) is obtained by replacing each entry xxx of uuu by νp(x)\nu_p(x)νp​(x) — the exponent of ppp in the prime factorization of xxx, as given by Mathlib's Nat.factorization, with the conventions νp(0)=0\nu_p(0)=0νp​(0)=0, νp(1)=0\nu_p(1)=0νp​(1)=0, and νp(x)=0\nu_p(x)=0νp​(x)=0 for every xxx whenever ppp is not prime — and then folding the resulting multiset of exponents with gcd⁡\gcdgcd, starting from 000:

Gp(u)  =  gcd⁡(0,  νp(x1),  …,  νp(xk)),u={ ⁣{x1,…,xk} ⁣}.G_p(u) \;=\; \gcd\bigl(0,\; \nu_p(x_1),\; \dots,\; \nu_p(x_k)\bigr), \qquad u = \{\!\{x_1,\dots,x_k\}\!\}.Gp​(u)=gcd(0,νp​(x1​),…,νp​(xk​)),u={{x1​,…,xk​}}.

Since gcd⁡\gcdgcd is commutative and associative and gcd⁡(0,a)=a\gcd(0,a)=agcd(0,a)=a, the value does not depend on the order of the fold: it is the greatest common divisor of the multiset of ppp-adic exponents of the entries, where exponent-000 entries are neutral (they do not force the result to 000), the empty board yields 000, and a board all of whose entries have exponent 000 yields 000. Example: G2({ ⁣{2,3} ⁣})=gcd⁡(1,0)=1G_2(\{\!\{2,3\}\!\}) = \gcd(1,0) = 1G2​({{2,3}})=gcd(1,0)=1; G2({ ⁣{1,1,8} ⁣})=gcd⁡(0,0,3)=3G_2(\{\!\{1,1,8\}\!\}) = \gcd(0,0,3) = 3G2​({{1,1,8}})=gcd(0,0,3)=3.

The move relation is as in the other statement: there exist m,nm,nm,n with m>1m>1m>1, n>1n>1n>1, an occurrence of mmm in sss and an occurrence of nnn in sss with that copy of mmm deleted, and

t  =  { ⁣{ gcd⁡(m,n) } ⁣}  +  { ⁣{ lcm⁡(m,n)gcd⁡(m,n) } ⁣}  +  (s∖{ ⁣{m} ⁣}∖{ ⁣{n} ⁣}).t \;=\; \{\!\{\,\gcd(m,n)\,\}\!\} \;+\; \Bigl\{\!\Bigl\{\,\tfrac{\operatorname{lcm}(m,n)}{\gcd(m,n)}\,\Bigr\}\!\Bigr\} \;+\; \bigl( s \setminus \{\!\{m\}\!\} \setminus \{\!\{n\}\!\} \bigr).t={{gcd(m,n)}}+{{gcd(m,n)lcm(m,n)​}}+(s∖{{m}}∖{{n}}).

1. Hypotheses, and what they exclude. There are two: hph_php​ (ppp is prime) and hhh (there is a move from sss to ttt).

  • hph_php​ — the conclusion does not mention it. The conclusion mentions ppp only as the index of the exponent function; nothing in it requires ppp prime. This hypothesis excludes no boards: it restricts the index ppp, so for every board pair the instances p=0p=0p=0, p=1p=1p=1, p=4p=4p=4, p=6p=6p=6, p=9p=9p=9, … are outside the scope. Concretely, with s={ ⁣{4,6} ⁣}s=\{\!\{4,6\}\!\}s={{4,6}} and t={ ⁣{2,12} ⁣}t=\{\!\{2,12\}\!\}t={{2,12}}, the instance p=4p=4p=4 is excluded even though both boards are otherwise in scope.
  • hhh — the conclusion does not mention it. The conclusion is a bare equality of two numbers computed from sss and from ttt; it refers to no move, no mmm, no nnn. This hypothesis excludes every pair of boards not related by a single move:
    • any sss having fewer than two occurrences of values greater than 111 is excluded entirely (no ttt whatsoever is in scope with it): e.g. s={ ⁣{1,1,9} ⁣}s = \{\!\{1,1,9\}\!\}s={{1,1,9}}, s={ ⁣{0,30} ⁣}s = \{\!\{0,30\}\!\}s={{0,30}}, s={ ⁣{ } ⁣}s = \{\!\{\,\}\!\}s={{}};
    • pairs related by zero moves or by more than one move are excluded: e.g. s=t={ ⁣{4,6} ⁣}s = t = \{\!\{4,6\}\!\}s=t={{4,6}} is excluded, and so is the pair s={ ⁣{4,6} ⁣}s=\{\!\{4,6\}\!\}s={{4,6}}, t={ ⁣{1,2,6} ⁣}t=\{\!\{1,2,6\}\!\}t={{1,2,6}} if it is not produced by one move;
    • a board that is not the exact output of a move is excluded as target: with s={ ⁣{4,6} ⁣}s = \{\!\{4,6\}\!\}s={{4,6}}, the target t={ ⁣{2,12} ⁣}t = \{\!\{2,12\}\!\}t={{2,12}} is in scope while t={ ⁣{2,12,1} ⁣}t = \{\!\{2,12,1\}\!\}t={{2,12,1}} is not.

2. The prime, and the non-prime case. Each side computes the greatest common divisor of the ppp-adic exponents of the entries of the board in question: the left side over the entries of ttt, the right side over the entries of sss (with the gcd⁡\gcdgcd-with-000 conventions above). When ppp is not prime — including p=0p=0p=0 and p=1p=1p=1 — the exponent function Nat.factorization is supported on primes, so νp(x)=0\nu_p(x)=0νp​(x)=0 for every entry xxx of every board; both sides are then the greatest common divisor of a multiset of zeros, namely 000, and the claimed equality would read 0=00=00=0. The hypothesis hph_php​ rules this case out: the statement is asserted only for prime ppp and says nothing whatsoever for composite ppp, for p=1p=1p=1, or for p=0p=0p=0.

3. Existence / availability of a move. Not applicable in the sense asked of the other statement: this statement has no existential conclusion. It is stated only for pairs already related by a move, and therefore says nothing about any board from which no move is possible.

4. Size. No hypothesis constrains the number of entries of sss or of ttt, and no size relation is asserted in the conclusion. Unfolding the move hypothesis, however, sss must contain at least two occurrences (an mmm, and an nnn in the remainder), and ttt is built by deleting two occurrences and adjoining two, so any pair in scope satisfies ∣t∣=∣s∣≥2|t| = |s| \ge 2∣t∣=∣s∣≥2. That is a consequence of the definition, not a separate claim, and no upper bound of any kind appears.

5. Degenerate cases.

  • Empty board: Gp({ ⁣{ } ⁣})=0G_p(\{\!\{\,\}\!\}) = 0Gp​({{}})=0, but the empty board can be neither sss nor ttt under the move hypothesis (sss needs at least two entries, and ttt receives two adjoined entries), so it is out of scope.
  • All 111s, e.g. { ⁣{1,1,1} ⁣}\{\!\{1,1,1\}\!\}{{1,1,1}}: Gp=gcd⁡(0,0,0)=0G_p = \gcd(0,0,0) = 0Gp​=gcd(0,0,0)=0. Such a board admits no move, so it is out of scope as sss; and since m,n>1m,n>1m,n>1 forces at least one of gcd⁡(m,n)\gcd(m,n)gcd(m,n), lcm⁡(m,n)/gcd⁡(m,n)\operatorname{lcm}(m,n)/\gcd(m,n)lcm(m,n)/gcd(m,n) to exceed 111, it is out of scope as ttt as well.
  • Contains 000: not excluded — this statement has no positivity hypothesis. A 000 entry can never be selected as mmm or nnn (both must exceed 111), so it survives any move, and νp(0)=0\nu_p(0)=0νp​(0)=0 makes it neutral in the gcd⁡\gcdgcd (a junk convention: 000 is divisible by every power of ppp, yet the exponent returned is 000). Concretely s={ ⁣{0,4,6} ⁣}s = \{\!\{0,4,6\}\!\}s={{0,4,6}} with m=4m=4m=4, n=6n=6n=6 gives t={ ⁣{2,12,0} ⁣}t = \{\!\{2,12,0\}\!\}t={{2,12,0}}, and for p=2p=2p=2 the statement asserts gcd⁡(1,2,0)=gcd⁡(2,1,0)\gcd(1,2,0) = \gcd(2,1,0)gcd(1,2,0)=gcd(2,1,0), i.e. 1=11 = 11=1.
  • Exactly one entry above 111: as a source, e.g. s={ ⁣{1,1,8} ⁣}s = \{\!\{1,1,8\}\!\}s={{1,1,8}} (where G2=3G_2 = 3G2​=3), no move exists, so it is out of scope. As a target it can occur: s={ ⁣{2,2} ⁣}s = \{\!\{2,2\}\!\}s={{2,2}} with m=n=2m=n=2m=n=2 gives t={ ⁣{2,1} ⁣}t = \{\!\{2,1\}\!\}t={{2,1}}, and the statement asserts gcd⁡(1,0)=gcd⁡(1,1)\gcd(1,0) = \gcd(1,1)gcd(1,0)=gcd(1,1), i.e. 1=11=11=1.
  • Hypotheses unsatisfiable: for non-prime ppp the first hypothesis is false and the statement is vacuous at that ppp; for any sss with fewer than two entries exceeding 111, or any pair not related by exactly one move, the second hypothesis is false and the statement is vacuous there. The two hypotheses are jointly satisfiable (e.g. p=2p=2p=2, s={ ⁣{4,6} ⁣}s=\{\!\{4,6\}\!\}s={{4,6}}, t={ ⁣{2,12} ⁣}t=\{\!\{2,12\}\!\}t={{2,12}}), so the statement is not vacuous overall.

Not asserted. The statement covers a single move only: it says nothing about reachability, about chains of moves, about terminal boards, or about invariance along a whole play. It does not assert that the common value is positive, nonzero, or bounded; does not assert anything for non-prime ppp; does not assert anything about the ordinary gcd of the entries themselves, nor about their product, sum, or cardinality; does not assert any inequality or monotonicity, only equality of two natural numbers; does not identify which entry realizes the exponent-gcd; does not claim that mmm and nnn are unique or determined by sss and ttt; does not claim a converse (that equality of these quantities implies a move); makes no use of bigPart (the exponents are taken over all entries of the board, including entries equal to 000 or 111), and imposes no positivity hypothesis on the entries.

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