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Section 16.1.3 -- adjacent transpositions lower bound

Proved
MarkovMixing.adjacent_transpositions_lower

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

The lazy random adjacent transpositions shuffle of a deck of nnn cards does nothing with probability 12\tfrac1221​ and otherwise swaps the cards in a uniformly chosen pair of neighbouring positions (i,i+1)(i,i+1)(i,i+1): the identity carries probability 12\tfrac1221​ and each of the n−1n-1n−1 adjacent transpositions probability 1/(2(n−1))1/\bigl(2(n-1)\bigr)1/(2(n−1)). Its stationary distribution is uniform. The mixing time tmixt_{\mathrm{mix}}tmix​ is the first time ttt at which max⁡x∥Pt(x,⋅)−unif∥TV≤14\max_x\|P^t(x,\cdot)-\mathrm{unif}\|_{TV}\le\tfrac14maxx​∥Pt(x,⋅)−unif∥TV​≤41​, with ∥μ−ν∥TV=max⁡A∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_A|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA​∣μ(A)−ν(A)∣ the total variation distance.

The theorem (§16.1.3 of Levin–Peres–Wilmer) asserts: for every n≥2n\ge2n≥2,

tmix  ≥  n2 (n−1)16.t_{\mathrm{mix}}\;\ge\;\frac{n^2\,(n-1)}{16}.tmix​≥16n2(n−1)​.

Order n3n^3n3 steps are necessary, matching the n3log⁡nn^3\log nn3logn upper bound up to the logarithm. The obstruction is transport: a single card performs a random walk on the nnn positions that advances only when its own position is selected, so moving it across the deck takes order n⋅n2n\cdot n^2n⋅n2 steps.

Preamble
import Definitions.Def_mm_shuffle
Formal statement
namespace MarkovMixing

/-- **§16.1.3** (LPW): for the lazy random adjacent transpositions shuffle
on `n` cards, `t_mix ≥ n²(n−1)/16`. -/
theorem adjacent_transpositions_lower (n : ℕ) (hn : 2 ≤ n) :
    (n : ℝ) ^ 2 * ((n : ℝ) - 1) / 16 ≤
      (tMix (groupWalk (adjacentTranspositionDist n))
        (uniformDist (Equiv.Perm (Fin n))) : ℝ) := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 16.1.3, pp. 219-220
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What the Lean code literally says, in plain math · claude-fable-5

For every natural number nnn with n≥2n \ge 2n≥2 (this holds for all such nnn, with no asymptotic threshold),

n2 (n−1)16  ≤  tmix(n),\frac{n^{2}\,(n-1)}{16} \;\le\; t_{\mathrm{mix}}^{(n)},16n2(n−1)​≤tmix(n)​,

where the right-hand side is a natural number (cast to a real) defined as follows, and on the left nnn is cast to a real and n−1n-1n−1 is real subtraction. The state space is the group SnS_nSn​ of permutations of {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1}. A weight function μn:Sn→R\mu_n : S_n \to \mathbb{R}μn​:Sn​→R is defined by: μn(g)=12\mu_n(g) = \tfrac12μn​(g)=21​ if ggg is the identity; otherwise μn(g)=12(n−1)\mu_n(g) = \dfrac{1}{2(n-1)}μn​(g)=2(n−1)1​ if ggg equals the transposition swapping iii and i+1i+1i+1 for some index iii with i+1<ni+1 < ni+1<n (an adjacent transposition; the second point is written (i+1) mod n(i+1)\bmod n(i+1)modn in the code but the guard i+1<ni+1<ni+1<n makes it literally i+1i+1i+1); and μn(g)=0\mu_n(g) = 0μn​(g)=0 for all other permutations. The transition matrix is the random-walk matrix Pn(x,y)=μn(y x−1)P_n(x,y) = \mu_n(y\,x^{-1})Pn​(x,y)=μn​(yx−1). The reference distribution is the constant function πn(g)=1/n!\pi_n(g) = 1/n!πn​(g)=1/n! on SnS_nSn​ (the uniform distribution). The distance between two functions μ,ν:Sn→R\mu,\nu : S_n \to \mathbb{R}μ,ν:Sn​→R is d(μ,ν)=sup⁡A⊆Sn∣∑g∈Aμ(g)−∑g∈Aν(g)∣d(\mu,\nu) = \sup_{A \subseteq S_n}\bigl|\sum_{g\in A}\mu(g) - \sum_{g\in A}\nu(g)\bigr|d(μ,ν)=supA⊆Sn​​​∑g∈A​μ(g)−∑g∈A​ν(g)​, the supremum over all finite subsets of the absolute difference of sums (note: no factor 12\tfrac1221​). The worst-case distance to πn\pi_nπn​ at time ttt is dn(t)=max⁡x∈Snd(Pnt(x,⋅), πn)d_n(t) = \max_{x\in S_n} d\bigl(P_n^{t}(x,\cdot),\,\pi_n\bigr)dn​(t)=maxx∈Sn​​d(Pnt​(x,⋅),πn​), using row xxx of the ttt-th matrix power. Finally, the mixing quantity is taken at the fixed threshold 14\tfrac1441​:

tmix(n)  =  inf⁡{ t∈N  ∣  dn(t)≤14 },t_{\mathrm{mix}}^{(n)} \;=\; \inf\bigl\{\, t \in \mathbb{N} \;\bigm|\; d_n(t) \le \tfrac14 \,\bigr\},tmix(n)​=inf{t∈N​dn​(t)≤41​},

which by the natural-number infimum convention equals 000 if no such ttt exists (in which case the claimed inequality would force n2(n−1)/16≤0n^2(n-1)/16 \le 0n2(n−1)/16≤0, impossible for n≥2n \ge 2n≥2, so the statement implicitly requires the set to be nonempty with a large infimum). The statement carries no hypothesis that PnP_nPn​ is stochastic or that πn\pi_nπn​ is stationary for it; the only hypothesis is n≥2n \ge 2n≥2. The inequality is non-strict and is a lower bound on the mixing quantity.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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