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A smaller residue-20 ancestor from divisibility by the thirteenth power of three

Proved
CollatzWork.residueAncestor_of_divisibility

by Sodelin · Sep 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

collatz-work-import

Let T:N→NT:\mathbb N\to\mathbb NT:N→N be the shortcut Collatz map: T(n)=n/2T(n)=n/2T(n)=n/2 for even nnn and T(n)=(3n+1)/2T(n)=(3n+1)/2T(n)=(3n+1)/2 for odd nnn. Write TkT^kTk for its kkk-fold iterate, with T0(n)=nT^0(n)=nT0(n)=n.

Let r∈Nr\in\mathbb Nr∈N satisfy 313∣(4r+1)3^{13}\mid(4r+1)313∣(4r+1). Then

∃m,b∈N,0<m<r,m≡20(mod27),Tb(m)=r.\exists m,b\in\mathbb N,\quad 0<m<r,\quad m\equiv20\pmod{27},\quad T^b(m)=r.∃m,b∈N,0<m<r,m≡20(mod27),Tb(m)=r.

The premise is only integer divisibility; a maximal power-of-three factorization is constructed within the proof. The divisor condition remains a genuine guard.

Preamble
import Std
import Init.Grind.Ordered.Module
import Definitions.Def_CollatzWork_ConvergenceStatement
import Definitions.Def_CollatzWork_ResidueAncestorStatement
import Theorems.Thm_CollatzWork_residueAncestor
import Theorems.Thm_CollatzWork_residueAncestor_factor_unit



Formal statement
theorem CollatzWork.residueAncestor_of_divisibility : ResidueAncestorDivisibilityStatement := by sorry

Source
https://github.com/Sodelin/Collatz-Conjecture-Work/blob/026aa4ad4be6453a005ab950b160a9f2204c5271/lean/CollatzWork/ResidueAncestor.lean#L148-L161

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