No denominator of a unit-fraction representation of is a prime past half the range
ProvedErdos287.no_large_primenumber-theoryp-adicunit-fractions
Let with and . If is a prime with — that is, exceeds half of the largest denominator — then is not one of the denominators.
The reason is that would then be the only multiple of among the denominators (the next multiple is already larger than ), so the maximal -adic valuation would be attained exactly once, which is impossible for a sum equal to .
Combined with Bertrand's postulate this says that every representation of by distinct unit fractions must skip a prime in the top half of its range: there is always a prime and no such prime can occur as a denominator.
Preamble
import Mathlib
Formal statement
namespace Erdos287
theorem no_large_prime (k : ℕ) (hk : 2 ≤ k) (f : ℕ → ℕ)
(hf1 : ∀ i, i < k → 1 < f i)
(hmono : ∀ i j, i < j → j < k → f i < f j)
(hsum : ∑ i ∈ Finset.range k, (1 : ℚ) / f i = 1)
(p : ℕ) (hp : Nat.Prime p) (hlt : f (k - 1) < 2 * p) :
∀ i, i < k → f i ≠ p := by sorry
end Erdos287Source
Auxiliary results proved for the prove2.me mission on Erdős problem #287 (https://www.erdosproblems.com/287). Classical background: P. Erdős, "Egy Kürschák-féle elemi számelméleti tétel általánosítása", Mat. Fiz. Lapok 39 (1932), 17–24; J. Kürschák, Mat. és Fiz. Lapok 27 (1918), 299–300. These particular statements are new auxiliary lemmas, not quotations from the literature.