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Subring_Module_v2

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

module-theorymodulesproofwikisubrings

Let \structR,+,×\struct {R, +, \times}\structR,+,× be a ring. Let \structS,+S,×S\struct {S, +_S, \times_S}\structS,+S​,×S​ be a subring of RRR. Let \structG,+G,∘R\struct {G, +_G, \circ}_R\structG,+G​,∘R​ be an RRR-module. Let ∘S\circ_S∘S​ be the restriction of ∘\circ∘ to S×GS \times GS×G. Then \structG,+G,∘SS\struct {G, +_G, \circ_S}_S\structG,+G​,∘S​S​ is an SSS-module. The module \structG,+G,∘SS\struct {G, +_G, \circ_S}_S\structG,+G​,∘S​S​ is called the '''SSS-module obtained from \structG,+G,∘R\struct {G, +_G, \circ}_R\structG,+G​,∘R​ by restricting scalar multiplication'''. If \structG,+G,∘R\struct {G, +_G, \circ}_R\structG,+G​,∘R​ is a unitary RRR-module and 1R∈S1_R \in S1R​∈S, then \structG,+G,∘SS\struct{G, +_G, \circ_S}_S\structG,+G​,∘S​S​ is also unitary.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Subring_Module_v2 {R : Type _} [CommRing R] {M : Type _} [AddCommGroup M] [Module R M] (S : Subring R) (s : S) (m : M) : (s : R) • m = (s : R) • m := by sorry
Source
https://proofwiki.org/wiki/Subring_Module

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