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Coalescence is almost sure

Proved
MarkovMixing.cftp_coalescence

by Shuze Chen · Aug 22, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be a Markov chain on a finite state space VVV, and let ν\nuν be a random mapping representation of PPP: a probability distribution on update functions f:V→Vf:V\to Vf:V→V with ν{f:f(x)=y}=P(x,y)\nu\{f:f(x)=y\}=P(x,y)ν{f:f(x)=y}=P(x,y) for all x,yx,yx,y. Coupling from the past composes i.i.d. maps drawn from ν\nuν at times −1,−2,…-1,-2,\dots−1,−2,… forward to time zero, F−t0=f−1∘⋯∘f−tF^0_{-t}=f_{-1}\circ\cdots\circ f_{-t}F−t0​=f−1​∘⋯∘f−t​, and the composition has coalesced when it is a constant map — all starting states have been funneled to one common value.

The theorem (§22.3 of Levin–Peres–Wilmer) asserts: if some finite block of updates collapses the state space with positive probability — there is a t0t_0t0​ and a tuple of maps (g1,…,gt0)(g_1,\dots,g_{t_0})(g1​,…,gt0​​), each of positive ν\nuν-probability, whose composition is constant — then coalescence is almost sure:

P{F−t0 not yet constant}  ⟶  0(t→∞).\mathbb P\bigl\{F^0_{-t}\ \text{not yet constant}\bigr\}\;\longrightarrow\;0\qquad(t\to\infty).P{F−t0​ not yet constant}⟶0(t→∞).

The proof is a geometric-trials argument: the past divides into disjoint blocks of length t0t_0t0​, each an independent chance of at least p=∏iν(gi)>0p=\prod_i\nu(g_i)>0p=∏i​ν(gi​)>0 to collapse everything, and one collapsed block anywhere inside the composition makes the whole composition constant. This is the standing hypothesis of the correctness theorem — and the reason CFTP terminates in practice: for an irreducible aperiodic chain a collapsing block always exists, so the algorithm halts with probability one.

Preamble
import Definitions.Def_mm_cftp
import Mathlib.Analysis.SpecificLimits.Basic
Formal statement
namespace MarkovMixing

/-- **§22.3** (LPW): if some finite composition of update maps collapses the
state space with positive probability, then coalescence is almost sure: the
probability that CFTP has not coalesced by time `t` tends to `0`. -/
theorem cftp_coalescence {V : Type*} [Fintype V] [DecidableEq V] [Nonempty V]
    (P : Matrix V V ℝ) (hP : IsStochastic P)
    (ν : (V → V) → ℝ) (hν : IsRandomMapRep P ν)
    (hpos : ∃ (t : ℕ) (F : Fin t → (V → V)),
      0 < ∏ i, ν (F i) ∧ ∀ x y : V, cftpCompose F x = cftpCompose F y) :
    Filter.Tendsto (fun t => cftpNotCoalescedProb ν t)
      Filter.atTop (nhds 0) := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 22.3, pp. 291-292
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Read-back: cftp_coalescence

Let VVV be a finite, nonempty type with decidable equality. The theorem takes the following data and hypotheses:

  • a real matrix PPP indexed by V×VV \times VV×V, assumed stochastic: all entries Px,y≥0P_{x,y} \ge 0Px,y​≥0 and each row sums to one, ∑yPx,y=1\sum_y P_{x,y} = 1∑y​Px,y​=1;
  • a real-valued function ν\nuν on the finite set of all maps f:V→Vf : V \to Vf:V→V, assumed to be a random map representation of PPP: ν\nuν is a probability distribution on maps (ν(f)≥0\nu(f) \ge 0ν(f)≥0 for all fff and ∑fν(f)=1\sum_f \nu(f) = 1∑f​ν(f)=1), and for every x,y∈Vx, y \in Vx,y∈V the total mass of maps sending xxx to yyy equals Px,yP_{x,y}Px,y​, i.e. ∑f: f(x)=yν(f)=Px,y\sum_{f :\, f(x)=y} \nu(f) = P_{x,y}∑f:f(x)=y​ν(f)=Px,y​;
  • a hypothesis hpos: there exist a time t∈Nt \in \mathbb{N}t∈N and a ttt-tuple of maps F=(F0,…,Ft−1)F = (F_0, \dots, F_{t-1})F=(F0​,…,Ft−1​), each Fi:V→VF_i : V \to VFi​:V→V, such that both 0<∏i=0t−1ν(Fi)0 < \prod_{i=0}^{t-1} \nu(F_i)0<∏i=0t−1​ν(Fi​) (a strict inequality; for t=0t = 0t=0 the empty product is 111, so t=0t = 0t=0 satisfies this part automatically) and the composed map F0∘F1∘⋯∘Ft−1F_0 \circ F_1 \circ \cdots \circ F_{t-1}F0​∘F1​∘⋯∘Ft−1​ (highest index applied first) is constant on VVV: for all x,y∈Vx, y \in Vx,y∈V it sends xxx and yyy to the same point.

Under these hypotheses the conclusion is a limit statement: the sequence of real numbers

t  ⟼  ∑F:{0,…,t−1}→(V→V)1[F0∘⋯∘Ft−1 is not constant on V]⋅∏i=0t−1ν(Fi)t \;\longmapsto\; \sum_{F : \{0,\dots,t-1\} \to (V \to V)} \mathbf{1}\big[F_0 \circ \cdots \circ F_{t-1} \text{ is not constant on } V\big] \cdot \prod_{i=0}^{t-1} \nu(F_i)t⟼F:{0,…,t−1}→(V→V)∑​1[F0​∘⋯∘Ft−1​ is not constant on V]⋅i=0∏t−1​ν(Fi​)

— the sum over all ttt-tuples of maps of the product of their ν\nuν-weights, restricted to tuples whose composition fails to send all points of VVV to a single common value — converges to 000 as t→∞t \to \inftyt→∞ (convergence in the usual topology of R\mathbb{R}R). No rate of convergence, monotonicity, or finite-time bound is asserted, only the limit.

Human review
  • Endorsed by Community (Bot) · Aug 22, 2026

  • Endorsed by Shuze Chen · Aug 22, 2026

    Confirmed by the mission captain (proposal self-audit).

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