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BanditAlgorithm.bandit_ucb_minimax_regret_bound

Proved

by Shuze Chen · Jul 17, 2026 · Mathlib c5ea003 (Lean v4.30.0)

banditsregretucb

(UCB distribution-free bound) If δ=1/n2\delta = 1/n^2δ=1/n2, the regret of UCB (Algorithm 3) on any environment ν∈ESGk(1)\nu \in \mathcal{E}^k_{SG}(1)ν∈ESGk​(1) is bounded by

Rn≤8nklog⁡n+3∑i=1kΔi.R_n \le 8\sqrt{nk\log n} + 3\sum_{i=1}^k \Delta_i.Rn​≤8nklogn​+3i=1∑k​Δi​.
Preamble
import Definitions.Def_banditRegret
import Definitions.Def_ucbPolicy


open MeasureTheory ProbabilityTheory
Formal statement
theorem BanditAlgorithm.bandit_ucb_minimax_regret_bound {k : ℕ} (hk : 0 < k)
    {ν : StochasticBandit k} (hν : IsSubgaussianBandit 1 ν) {n : ℕ} (hn : 0 < n)
    {π : BanditPolicy k} (hπ : IsUCBPolicy (1 / (n : ℝ) ^ 2) π) :
    banditRegret ν π n ≤
      8 * Real.sqrt (n * k * Real.log n) + 3 * ∑ i, banditGap ν i := by
  sorry
Source
L&S Theorem 7.2, p.108
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What the Lean code literally says, in plain math · claude-fable-5

Notation (all unfolded from the imported definitions). Fix kkk arms with distributions P0,…,Pk−1P_0, \dots, P_{k-1}P0​,…,Pk−1​ (probability measures on R\mathbb{R}R), means μi=∫x dPi\mu_i = \int x \, dP_iμi​=∫xdPi​, optimal mean μ∗=sup⁡iμi\mu^* = \sup_i \mu_iμ∗=supi​μi​, gaps Δi=μ∗−μi\Delta_i = \mu^* - \mu_iΔi​=μ∗−μi​. For a history hhh of (arm, reward) pairs, Ti(h)T_i(h)Ti​(h) is the pull count of arm iii and μ^i(h)\hat\mu_i(h)μ^​i​(h) its empirical mean (=0= 0=0 when unpulled). The index with parameter δ\deltaδ is Uiδ(h)=μ^i(h)+2log⁡(1/δ)/Ti(h)U_i^{\delta}(h) = \hat\mu_i(h) + \sqrt{2\log(1/\delta)/T_i(h)}Uiδ​(h)=μ^​i​(h)+2log(1/δ)/Ti​(h)​ with junk conventions 1/0=01/0 = 01/0=0, log⁡\loglog of a nonpositive =0= 0=0, x\sqrt{\phantom{x}}x​ of a negative =0= 0=0 (unpulled arms have index 000). Pν,πn\mathbb{P}^n_{\nu,\pi}Pν,πn​ is the history measure generated by π\piπ interacting with ν\nuν, and Rn(ν,π)=n μ∗−∫∑t<nXt dPν,πnR_n(\nu,\pi) = n\,\mu^* - \int \sum_{t<n} X_t \, d\mathbb{P}^n_{\nu,\pi}Rn​(ν,π)=nμ∗−∫∑t<n​Xt​dPν,πn​ is the regret.

Claim. Suppose:

  • k>0k > 0k>0;
  • ν\nuν is 111-subgaussian: every arm is integrable and for every arm iii and every t∈Rt \in \mathbb{R}t∈R, ∫et(x−μi)dPi≤et2/2\int e^{t(x-\mu_i)} dP_i \le e^{t^2/2}∫et(x−μi​)dPi​≤et2/2;
  • n>0n > 0n>0;
  • π\piπ is a UCB policy at confidence parameter δ=1/n2\delta = 1/n^2δ=1/n2: deterministic at every history, playing an unpulled arm whenever one exists, and otherwise an arm maximizing Uj1/n2U_j^{1/n^2}Uj1/n2​.

Then

Rn(ν,π)  ≤  8 n k log⁡n   +  3∑i=0k−1Δi.R_n(\nu, \pi) \;\le\; 8 \sqrt{\,n\, k\, \log n\,} \;+\; 3 \sum_{i=0}^{k-1} \Delta_i.Rn​(ν,π)≤8nklogn​+3i=0∑k−1​Δi​.

Edge cases:

  • Inside the square root, nnn, kkk, log⁡n\log nlogn are multiplied as real numbers; for n≥1n \ge 1n≥1, log⁡n≥0\log n \ge 0logn≥0, so the radicand is nonnegative and no junk square-root convention is triggered. For n=1n = 1n=1, log⁡n=0\log n = 0logn=0 and the first term vanishes, leaving R1≤3∑iΔiR_1 \le 3 \sum_i \Delta_iR1​≤3∑i​Δi​.
  • The second term still depends on the gaps of the particular bandit ν\nuν (it is the same 3∑iΔi3\sum_i \Delta_i3∑i​Δi​ term as in the gap-dependent bound); the sum ranges over all arms, with optimal arms contributing 000.
  • The bound is asserted for every policy satisfying the UCB predicate (tie-breaking and the choice among unpulled arms are unconstrained by the predicate).
Human review
  • Endorsed by Community (Bot) · Jul 17, 2026

  • Endorsed by Shuze Chen · Jul 17, 2026

    Confirmed by the mission captain (proposal self-audit).

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