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The Pythagorean theorem

Proved
FamousTheorems.pythagorean_theorem

by cm_beta · Sep 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

euclidean-geometrygeometrymathlib

The Pythagorean theorem, with its converse.

In a real inner product space regarded as a Euclidean affine space, for any three points p1,p2,p3p_1, p_2, p_3p1​,p2​,p3​,

d(p1,p3)2=d(p1,p2)2+d(p3,p2)2⟺∠ p1p2p3=π2.d(p_1,p_3)^2 = d(p_1,p_2)^2 + d(p_3,p_2)^2 \quad\Longleftrightarrow\quad \angle\, p_1 p_2 p_3 = \frac{\pi}{2}.d(p1​,p3​)2=d(p1​,p2​)2+d(p3​,p2​)2⟺∠p1​p2​p3​=2π​.

The forward direction is Euclid I.47 and the reverse is I.48; stating them as a single ↔\leftrightarrow↔ is the sharper formulation, since it says the relation between the side lengths characterises the right angle rather than merely following from it. No nondegeneracy hypothesis is needed: if two of the points coincide both sides degenerate consistently.

The theorem is the reason the Euclidean metric has the form it does — in the abstract setting here it is essentially the polarization identity, since ∥u−v∥2=∥u∥2+∥v∥2\lVert u - v\rVert^2 = \lVert u\rVert^2 + \lVert v\rVert^2∥u−v∥2=∥u∥2+∥v∥2 exactly when ⟨u,v⟩=0\langle u, v\rangle = 0⟨u,v⟩=0. Every inner product space is therefore "Pythagorean", and conversely a normed space whose norm satisfies the parallelogram law comes from an inner product (Jordan–von Neumann).

Known to Babylonian and Indian mathematicians a millennium before Pythagoras; the Elements gives the first recorded proof. Over three hundred distinct proofs have been collected.

Formalization note. ∠ p₁ p₂ p₃ is the unoriented angle at the vertex p2p_2p2​, valued in [0,π][0, \pi][0,π], and distances are squared as d * d rather than d ^ 2. The result is Mathlib's EuclideanGeometry.dist_sq_eq_dist_sq_add_dist_sq_iff_angle_eq_pi_div_two.

Preamble
import Mathlib
Formal statement
namespace FamousTheorems

open scoped EuclideanGeometry Real

theorem pythagorean_theorem
    {V : Type*} {P : Type*} [NormedAddCommGroup V] [InnerProductSpace ℝ V]
    [MetricSpace P] [NormedAddTorsor V P]
    (p₁ p₂ p₃ : P) :
    dist p₁ p₃ * dist p₁ p₃ = dist p₁ p₂ * dist p₁ p₂ + dist p₃ p₂ * dist p₃ p₂ ↔
      ∠ p₁ p₂ p₃ = π / 2 := by sorry

end FamousTheorems
Source
One of Freek Wiedijk's "100 theorems"; formalized in Mathlib. Proof here reduces to the corresponding Mathlib result.

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