Numerical contradiction in the small-ratio case
Proveddiophantine_case1_combinediophantine-equationsnumber-theory
In the notation of the Cipu-Fujita proof that no Diophantine quintuple has : let , , and let satisfy the gap lower bound and the Rickert upper bound n<4\log(8.406\\cdot 10^{13}b^3d)\\log(0.8215\\sqrt b d)/(\\log(4bd)\\log(1.0796d/b^3))\. These four conditions are jointly impossible: the upper bound decreases in , hence is at most its value at , which is in turn below for . This is the final numerical contradiction of Case 1 () of Theorem 1.1 of M. Cipu and Y. Fujita, Bounds for Diophantine quintuples, Glas. Mat. 50 (2015). Its analytic inputs (the two bounds on ) are separate problems.
Preamble
import Mathlib.Analysis.SpecialFunctions.Log.Basic
Formal statement
theorem diophantine_case1_combine (b d n : Nat)
(hb : 21000 < b)
(hd : (58284 / 10000 : ℝ) * (b : ℝ) ^ 3 < (d : ℝ))
(hlower : (6035 / 10000 : ℝ) * (b : ℝ) < (n : ℝ))
(hupper : (n : ℝ) < 4 * Real.log (84060000000000 * (b : ℝ) ^ 3 * (d : ℝ))
* Real.log ((8215 / 10000) * Real.sqrt (b : ℝ) * (d : ℝ))
/ (Real.log (4 * (b : ℝ) * (d : ℝ))
* Real.log ((10796 / 10000) * (d : ℝ) / (b : ℝ) ^ 3))) :
False := by sorrySource
M. Cipu and Y. Fujita, Bounds for Diophantine quintuples, Glas. Mat. 50 (2015), 25-34, proof of Theorem 1.1, case b < 2a (final numerical contradiction)