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Existence of a Bellman optimality solution for a finite MDP

Proved
BanditAlgorithm.mdp_exists_bellman_optimality_solution

by Grace · Aug 2, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-decision-processesreinforcement-learning

Let MMM be a finite MDP with S≥1S \ge 1S≥1 states, A≥1A \ge 1A≥1 actions, rewards ra(s)∈[0,1]r_a(s) \in [0,1]ra​(s)∈[0,1] and finite diameter D(M)<∞D(M) < \inftyD(M)<∞. Then there exist a gain ρ∈[0,1]\rho \in [0,1]ρ∈[0,1], a value function v:S→Rv : \mathcal{S} \to \mathbb{R}v:S→R, and a deterministic memoryless policy f:S→Af : \mathcal{S} \to \mathcal{A}f:S→A such that

span(v)  ≤  ρ D(M),ra(s)+⟨Pa(s),v⟩  ≤  ρ+v(s)  for all a,ρ+v(s)  =  rf(s)(s)+⟨Pf(s)(s),v⟩,\mathrm{span}(v) \;\le\; \rho\, D(M), \qquad r_a(s) + \langle P_a(s), v\rangle \;\le\; \rho + v(s) \ \ \text{for all } a, \qquad \rho + v(s) \;=\; r_{f(s)}(s) + \langle P_{f(s)}(s), v\rangle,span(v)≤ρD(M),ra​(s)+⟨Pa​(s),v⟩≤ρ+v(s)  for all a,ρ+v(s)=rf(s)​(s)+⟨Pf(s)​(s),v⟩,

and ρ=ρ∗\rho = \rho^{*}ρ=ρ∗ is the optimal gain of MMM. The last two displays together say that (ρ,v)(\rho, v)(ρ,v) solves the average-reward Bellman optimality equation

ρ+v(s)  =  max⁡a(ra(s)+⟨Pa(s),v⟩),\rho + v(s) \;=\; \max_{a} \big( r_a(s) + \langle P_a(s), v\rangle \big),ρ+v(s)=amax​(ra​(s)+⟨Pa​(s),v⟩),

with fff a greedy — hence gain-optimal — policy; since ρ≤1\rho \le 1ρ≤1 the span bound gives span(v)≤D(M)\mathrm{span}(v) \le D(M)span(v)≤D(M).

This is Theorem 38.2 of Lattimore and Szepesvári, whose proof is left to their Exercise 38.10. It is what makes UCRL2 well defined: the algorithm computes an optimistic solution of the optimality equation of the extended MDP and plays greedily, and both the optimism step (Eq. 38.17) and the span bound of Eq. (38.19) are read off the equation.

The proof is the vanishing-discount argument. For each γ<1\gamma < 1γ<1 let VγV_\gammaVγ​ be the γ\gammaγ-discounted value function and put ργ=(1−γ)max⁡sVγ(s)∈[0,1]\rho_\gamma = (1-\gamma)\max_s V_\gamma(s) \in [0,1]ργ​=(1−γ)maxs​Vγ​(s)∈[0,1]. Splitting ⟨Pa(s),Vγ⟩\langle P_a(s), V_\gamma\rangle⟨Pa​(s),Vγ​⟩ as γ⟨Pa(s),Vγ⟩+(1−γ)⟨Pa(s),Vγ⟩\gamma\langle P_a(s), V_\gamma\rangle + (1-\gamma)\langle P_a(s), V_\gamma\rangleγ⟨Pa​(s),Vγ​⟩+(1−γ)⟨Pa​(s),Vγ​⟩ and bounding the second term by (1−γ)max⁡sVγ(s)(1-\gamma)\max_s V_\gamma(s)(1−γ)maxs​Vγ​(s) shows that (ργ,Vγ)(\rho_\gamma, V_\gamma)(ργ​,Vγ​) solves the average-reward Bellman inequality; hence span(Vγ)≤ργD(M)≤D(M)\mathrm{span}(V_\gamma) \le \rho_\gamma D(M) \le D(M)span(Vγ​)≤ργ​D(M)≤D(M), uniformly in γ\gammaγ. The recentred functions Vγ−Vγ(s0)V_\gamma - V_\gamma(s_0)Vγ​−Vγ​(s0​) therefore range in the compact cube [−D,D]S[-D, D]^{\mathcal S}[−D,D]S while ργ\rho_\gammaργ​ ranges in [0,1][0,1][0,1], and the greedy policies range over a finite set; so along a subsequence γk↑1\gamma_k \uparrow 1γk​↑1 the greedy policy is a fixed fff and the pair converges. In the limit the inequality persists, and the defect in the greedy equality — which equals (1−γ)(max⁡sVγ(s)−⟨Pf(s)(s),Vγ⟩)(1-\gamma)\big(\max_s V_\gamma(s) - \langle P_{f(s)}(s), V_\gamma\rangle\big)(1−γ)(maxs​Vγ​(s)−⟨Pf(s)​(s),Vγ​⟩) and so lies between 000 and (1−γ)D(M)(1-\gamma) D(M)(1−γ)D(M) — vanishes. That ρ\rhoρ is the optimal gain is then the two halves of the verification argument: the inequality gives ρ∗≤ρ\rho^{*} \le \rhoρ∗≤ρ and the equality along fff gives ρ≤ρ∗\rho \le \rho^{*}ρ≤ρ∗.

The uniform span bound is exactly the point at which the finiteness of the diameter enters; without it the recentred discounted value functions need not be bounded and the limit may fail to exist.

Preamble
import Definitions.Def_FiniteMDPLearning
import Mathlib.Probability.Kernel.Composition.IntegralCompProd

open MeasureTheory ProbabilityTheory
Formal statement
theorem BanditAlgorithm.mdp_exists_bellman_optimality_solution {S A : ℕ} (hS : 0 < S)
    (hA : 0 < A) (M : FiniteMDP S A) (hD : mdpDiameterENN M ≠ ⊤) :
    ∃ (ρ : ℝ) (v : Fin S → ℝ) (f : Fin S → Fin A),
      0 ≤ ρ ∧ ρ ≤ 1 ∧
      (∀ s s', v s - v s' ≤ ρ * mdpDiameter M) ∧
      (∀ s a, M.r s a + ∑ s', (M.P s a s' : ℝ) * v s' ≤ ρ + v s) ∧
      (∀ s, ρ + v s = M.r s (f s) + ∑ s', (M.P s (f s) s' : ℝ) * v s') ∧
      mdpOptimalGain M = ρ := by
  sorry
Source
Lattimore & Szepesvari, Bandit Algorithms (CUP 2020), Theorem 38.2 (Section 38.2, printed p. 521 / PDF p. 530; proof left to Exercise 38.10); Puterman, Markov Decision Processes (Wiley 1994), Chapter 8 (the vanishing-discount approach to the average-reward optimality equation).

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