Base series of Conjecture 3.2: $\frac{\binom{2k}{k}^2\binom{3k}{k}}{(-12)^{3k}}(51k+7)=\frac{12\sqrt3}{\pi}$

Initializing...

Base series of Conjecture 3.2: $\frac{\binom{2k}{k}^2\binom{3k}{k}}{(-12)^{3k}}(51k+7)=\frac{12\sqrt3}{\pi}$ · Prove2Me